a rectangle has a perimeter of 35 1/2 feet if the length is 12 feet, what is the area of the rectangle

We know that perimeter is all of the sides of an object added together. Since the length is 12 feet, that means that 24 feet (2 sides of the rectangle) is the length. That leaves us with 11 1/2 feet. This needs to be divided by 2 to find the width since there are 2 sides for width. 11 1/2 / 2 = 5 3/4. To find the area. (l x w), you can multiply 12 by 5 3/4 to get 69. Now write the correct units which are feet squared.

johanrusli johanrusli · Answer 2 · 2019-09-28T09:07:34+02:00

Area of the rectangle is 69 feet²

Further explanation

To solve the above questions, we need to recall some of the formulas as follows:

Area of Rectangle = Length × Width

Perimeter of Rectangle = 2 × ( Length + Width )

Let us now tackle the problem !

Given:

Perimeter of Rectangle = P = 35¹/₂ feet

Length of Rectangle = L = 12 feet

Unknown:

Area of Rectangle = A = ?

Solution:

This problem is about Area and Perimeter of Rectangle.

Let's find the width of Rectangle.

[tex]\texttt{Perimeter of Rectangle} = 2( \texttt{Length} + \texttt{Width} )[/tex]

[tex]35\frac{1}{2} = 2( 12 + \texttt{Width} )[/tex]

[tex]35\frac{1}{2} \div 2 = ( 12 + \texttt{Width} )[/tex]

[tex]17\frac{3}{4} = ( 12 + \texttt{Width})[/tex]

[tex]\texttt{Width} = 17\frac{3}{4} - 12[/tex]

[tex]\texttt{Width} = \boxed {5\frac{3}{4} ~ \texttt{feet}}[/tex]

Let's find the area of Rectangle.

[tex]\texttt{Area of Rectangle} = \texttt{Length} \times \texttt{Width}[/tex]

[tex]A = L \times W[/tex]

[tex]A = 12 \times 5\frac{3}{4}[/tex]

[tex]A = \boxed {69 ~ \texttt{feet}^2}[/tex]

Learn more

The perimeter of a polygon : https://brainly.com/question/6361596
The perimeter of a rectangle : https://brainly.com/question/7619923
The perimeter of a triangle : https://brainly.com/question/2299951

Answer details

Grade: College

Subject: Mathematics

Chapter: Two Dimensional Figures

Keywords: Perimeter, Area , Square , Rectangle , Side , Length , Width