[tex]\bf (\stackrel{x_1}{2}~,~\stackrel{y_1}{-3})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{-3}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-3-(-3)}{6-2}\implies \cfrac{-3+3}{4}\implies \cfrac{0}{4}\implies 0[/tex]
Hello!
Step-by-step explanation:
Slope: [tex]\frac{Y^2-Y^1}{X^2-X^1}=\frac{rise}{run}[/tex]
[tex]\frac{(-3)-(-3)=-3+3=0}{6-2=4}=\frac{0}{-4}=0[/tex]
Therefore, the slope is 0.
I think the answer is 0.
Have a nice day! :)
Have a great day!
-Charlie
:)
:D
