Respuesta :
distance traveled by a uniformly accelerated bike is given as
[tex]d = \frac{v_f + v_i}{2} (t)[/tex]
here we know that
[tex]v_f = 25 m/s[/tex]
[tex]v_i = 15 m/s[/tex]
[tex]t = 15 s[/tex]
now we will have from above equation
[tex]d = \frac{15 + 25}{2} (15)[/tex]
[tex]d = 20 (15) = 300 m[/tex]
so it will cover the total distance of 300 m
The distance traveled by the motorbike is 300 m.
How do you calculate the distance?
Given that initial velocity u is 15 m/s and final velocity v is 25 m/s within the time t = 15 seconds.
The distance covered by the motorbike is calculated by the formula given below.
[tex]s = \dfrac {1}{2}(u+v)t[/tex]
[tex]s = \dfrac {1}{2}(15+25)\times 15[/tex]
[tex]s = 300 \;\rm m[/tex]
Hence we can conclude that the distance traveled by the motorbike is 300 m.
To know more about the velocity and distance, follow the link given below.
https://brainly.com/question/12626613.
