Answer:
No rational roots
Step-by-step explanation:
According to the rational root theorem, any rational root of a polynomial will be of the form p/q, where p is a factor of the constant term and q is a factor of the leading coefficient.
Here in this case, q = 1 and p = -3.
This means that the only possible rational factors are:
1, -1, 3 and -3
But if we check, none of the above values are the roots for [tex]x^3-x^2-x-3=0[/tex].
