Answer:
(x-4)^2
Step-by-step explanation:
[tex]x^2-8x+16[/tex]
First multiply the outer coefficients 1 and 16: 1x16=16. Now, the name of the game is to try to figure out if 16 has factors that when added or subtracted will give you the middle term -8. List factors of 16: 1x16, 2x8, 4x4. By looking at these pairs of numbers we can see that 4 and 4 will give you 8 but specifically -4-4=-8 and so:
[tex]x^2-8x+16=(x-4)(x-4)=(x-4)^2[/tex]
