27. The density of nickel is 8.91 g/cm3. How large a cube, in cm3, would contain 2.00 x 10^24 atoms of nickel? Use dimensional analysis to solve and show all work including units on every number! (5 points)

Respuesta :

Answer : The volume of the cube is, [tex]21.88cm^3[/tex]

Solution : Given,

Density of nickel = [tex]8.91g/cm^3[/tex]

Number of nickel atoms = [tex]2\times 10^{24}[/tex]

Molar mass of nickel = 58.7 g/mole

First we have to calculate the moles of nickel.

As, [tex]6.022\times 10^{23}[/tex] atoms form 1 mole of nickel

So, [tex]2\times 10^{24}[/tex] atoms form [tex]\frac{2\times 10^{24}}{6.022\times 10^{23}}=3.321[/tex] moles of nickel

The moles of nickel = 3.321 moles

Now we have to calculate the mass of nickel.

[tex]\text{ Mass of Ni}=\text{ Moles of Ni}\times \text{ Molar mass of Ni}[/tex]

[tex]\text{ Mass of Ni}=(3.321moles)\times (58.7g/mole)=194.94g[/tex]

The mass of nickel = 194.94 g

Now we have to calculate the volume of nickel.

[tex]Density=\frac{Mass}{Volume}[/tex]

[tex]8.91g/cm^3=\frac{194.94g}{Volume}[/tex]

[tex]Volume=21.88cm^3[/tex]

Therefore, the volume of the cube is, [tex]21.88cm^3[/tex]

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