Answer:
2log₂(x) +3log₂(y) -log₂(9)
Step-by-step explanation:
The applicable rules of logarithms are ...
... log(ab) = log(a) + log(b)
... log(a^b) = b·log(a)
... log(a/b) = log(a) -log(b)
Note that these are essentially all the same rule, expressed in different forms. For example, ...
... log(a·a) = log(a²) = log(a) +log(a) = 2·log(a)
The same sort of result obtains with larger exponents or exponents that are negative.
... log(a/b) = log(a·b⁻¹) = log(a) +(-1)log(b) = log(a) -log(b)
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Applying these to your problem, you have ...
... log₂(x²y³/9) = log₂(x²) +log₂(y³) -log₂(9)
... = 2log₂(x) +3log₂(y) -log₂(9)
