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what was the hikers average velocity during part c of the hike?

velocity = displacement /change in time


so the chart, wasn't able to add pic but it says four times.


the distance was 6km east. the time started at 8:00 a.m and ended 9:00 a.m


for part hike b, distance was 4 km south 9:00 a.m to 9:45 a.m


part c, distance was 6 km west, an time was 9:45 a.m to 10:45 a.m.


and part d, 8 k.m north, and the time was from 10:45 a.m to 12:30




choice options:


6 km/h west

0.10 km/h north

4.0 km/h south

10 km/h southwest





(if correct i will give brainly.)

Respuesta :

ashbeaver2005

Hi, sorry for the late answer, but the answer is A) 6 km/h west, i took the test

hope this helps!


skyluke89

Answer:

6 km/h west

Explanation:

During part c of the hike, the hiker moved 6 km west, and the time was 9.45 am to 10.45 am.

So, we have:

- displacement: d = 6 km west

- time taken: from 9.45 am to 10.45 am = 1 hour

Therefore, the average velocity is given by the ratio between displacement and time taken:

[tex]v=\frac{d}{t}=\frac{6 km}{1 h}=6 km/h[/tex]

and the direction is the same as the displacement (west)

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