Answer:
add 7 to 9 times k : 7+9k
c cubed minus the product of 5 and q plus 4 : [tex]c^{3} - 5q + 4[/tex]
twice r plus 7 is equal to 45 minus r : 2r+7=45-r
Product of h and 4 is subtracted from one-fifth of x is 35 :(h*4) - 1/5*x
one third of the difference bewteen 6 and p is added to 8 : (6-p)+8
