What is the m∠BKD (URGENT)
What are the theorems we can use?
Probably the most relevant is the angle at a point on the circle subtended by a chord has a measure equal to half the arc indicated by the chord.
By the theorem,
angle AEB = angle ADB = (1/2) arc AC = (1/2) 110 = 55 deg
angle BAE = angle DBE = (1/2) arc DE = (1/2) 130 = 65 deg
angle BKD + angle KDB + angle DBK = 180 deg
angle BKD + angle ADB + angle DBE = 180 deg
angle BKD = 180 - 55 - 65 = 60 degrees
Answer: 60 degrees