Answer:
So, the width of rectangle is
[tex]W=x^2+7x+12[/tex]
Step-by-step explanation:
We are given area
[tex]A=x^3+12x^2+47x+60[/tex]
length is
[tex]L=(x+5)[/tex]
we know that formula of area of rectangle as
[tex]A=L\times W[/tex]
where
A is area of rectangle
W is width of rectangle
L is length of rectangle
so, we can plug value
[tex]x^3+12x^2+47x+60=(x+5)\times W[/tex]
now, we can solve for W
[tex]W=\frac{x^3+12x^2+47x+60}{(x+5)}[/tex]
we can use synthetic division
so, we got
[tex]W=\frac{x^3+12x^2+47x+60}{(x+5)}=x^2+7x+12[/tex]
