Answer:
[tex]\frac{x^3-3x^2+4x-7}{x-3} =(x^2+4)+\frac{5}{x-3}[/tex]
Step-by-step explanation:
We are given polynomial as
[tex]P(x)=x^3-3x^2+4x-7[/tex]
and it is divided by x=3 or x-3
we can use synthetic division
so, we got
Remainder =5
Quotient is
[tex]=x^2+0x+4[/tex]
[tex]=x^2+4[/tex]
we can write as
[tex]\frac{x^3-3x^2+4x-7}{x-3} =(x^2+4)+\frac{5}{x-3}[/tex]
