Respuesta :
Answer:
Dimension of rectangular playing filed is 53 yards by 115 yards
Step-by-step explanation:
The length of rectangular playing filed is 9 yards more than double the width.
Let us suppose width of rectangular field = x yard
Width (w)= x yards
Length (l)= 2x+9
Perimeter of Rectangular field = 2(l+w)
We are given perimeter of rectangular playing filed = 336 yards
2(2x+9+x)=336
Now we solve for x
3x+9=168
3x=159
x=53 yards
Width = 53 yards
Length = 2(53)+9 = 115 yards
Thus, Dimension of rectangular playing filed is 53 yard by 115 yards
You can use the given description to form a symbolic expression for length and width. The given parameter will then help you to get the value of unknown measures.
The dimensions of the given rectangle are
Length = 112 yards
Width = 56 yards
How to get the unknown dimensions of a rectangle from given parameter?
Since we are given length in terms of its width, thus, lets suppose that
width = [tex]x[/tex] yards.
Then, we have:
Length = double of width = [tex]2x[/tex] yards
The perimeter of a rectangle = [tex]\rm 2(length + width) = 336 \: yards[/tex] (given)
(remember that many times, when using letters or symbols, we hide multiplication and write two things which are multiplied, close to each other. As in [tex]2 \times x = 2x[/tex] )
Using above values for length and width in perimeter, we get
[tex]\rm 2(length + width) = 336\: yards\\2(x + 2x) = 336\\2(3x) = 336\\6x = 336\\\\\text{Dividing both the sides by 6}\\\\\dfrac{6x}{6} = \dfrac{336}{6}\\\\x = 56 \: yards = width\\[/tex]
Thus, length is double of width = 2 times 56 = 112 yards.
Thus,
The dimensions of the given rectangle are
Length = 112 yards
Width = 56 yards
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