When 2/5 of the koi was given away, there were still b koi and k goldfish left in the pond. How many koi and goldfish were there initially?

Respuesta :

Answer:

Step-by-step explanation:

Alright, lets get started.

Suppose initially there were x Koi in pool.

[tex]\frac{2}{5}[/tex] of Koi were taken away means, number of fish taken away : [tex]\frac{2}{5}x[/tex]

So, remaining Koi will be = [tex]x - \frac{2}{5}x=\frac{3}{5}x[/tex]

There are still b KOi remaining as per question, so

[tex]\frac{3}{5}x=b[/tex]

So, [tex]x=\frac{5}{3}b[/tex]

Means initially there were [tex]\frac{5}{3}b[/tex]Koi.

k goldfish were left in pool.

So number of remaining fish were = [tex]\frac{5}{3}b + k[/tex]

This is the answer:

Hope it will help :)


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