Answer:
3 and -8 are the zeroes of polynomial.
Option A and D are correct.
Step-by-step explanation:
Given the polynomial
[tex]f(x)=(x-3)(x+8)[/tex]
we have to find the zeroes of the above polynomial.
Zeroes of polynomial are those values which makes the value of polynomial 0 when substituted.
∴ to find the zeroes we have to substitute the polynomial equals to 0
[tex]f(x)=(x-3)(x+8)=0[/tex]
which implies
[tex]x-3=0, x+8=0[/tex]
[tex]x=3, x=-8[/tex]
Hence, 3 and -8 are the zeroes of polynomial.
Option A and D are correct.
