Respuesta :
Answer:
Area of rectangle =[tex]11y^6[/tex]
Step-by-step explanation:
Let l be the length of rectangle and w is the width of rectangle respectively.
Given: Length of rectangle is [tex]11y^4[/tex] and width of rectangle is [tex]y^2[/tex]
⇒[tex]l =11y^4[/tex] and [tex]w =y^2[/tex]
To find the area of rectangle:
Area of Rectangle(A) is equal to multiply its length by its width.
i.e, [tex]A = l \times w[/tex]
Substitute the given values of l and w in above formula we get;
[tex]A = 11y^4 \times y^2[/tex]
We know that: [tex]a^n \times a^m = a^{n+m}[/tex]
Then;
[tex]A = 11y^{4+2}= 11y^6[/tex]
therefore, the area of rectangle is, [tex]11y^6[/tex]
