Respuesta :

kenmyna

 The [Oh-]  in the  solution  with a POh of 11.25  is 5.623 x 10^-12 M


  calculation

POH= - log [ OH-]

Therefore  - log [oH-]  =11.25

 To calculate [oh-]  concentration find the antilog  of 11.35

 =  10^- 11.25  =  5.623  x 10^-12 M

Answer:

5.62*10^-12

Explanation:

Acellus

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