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Identify the equations that represent reactions that could occur. Select all that apply.

A) BaCl2(aq) + Na2SO4(aq) ==> BaSO4(s) + 2NaCl(aq)

B) NaBr(aq) + KCl(aq) ==> NaCl(aq) + KCl(aq)

C) NH4NO3(aq) + AgClO3(aq) ==> AgNO3(aq) + NH4ClO3(aq)

D) HCH3COO(aq) + NaHCO3(aq) ==> NaCH3COO(aq) + CO2(g) + H2O(l)

E) 2NaOH(aq) + CaCl2(aq) ==> 2NaCl(aq) + Ca(OH)2(s)

Respuesta :

Chlidonias

A reaction is apparently said to occur if it proceeds via the formation of a precipitate or a gaseous product, or a visible color change is observed after the reaction.

A)[tex]BaCl_{2}(aq)+Na_{2}SO_{4}(aq)-->BaSO_{4}(s)+2NaCl(aq)[/tex]: This reaction occurs as there is a formation of white precipitate of barium sulfate.

B) NaBr(aq)+KCl(aq)-->NaCl(aq)+KCl(aq): This reaction does not occur because all the ions just remain as spectator ions in the solution as the products are aqueous too.

C) [tex]NH_{4}NO_{3}(aq)+AgClO_{3}(aq)-->AgNO_{3}(aq)+NH_{4}ClO_{3}(aq)[/tex]: This reaction does not occur because all the ions just remain as spectator ions in the solution as the products are aqueous too.

D)[tex]HCH_{3}COO(aq)+NaHCO_{3}(aq)-->NaCH_{3}COO(aq)+CO_{2}(g)+H_{2}O(l)[/tex]:This reaction can be observed as this proceeds via the formation of gas bubbles of carbon dioxide.

E) [tex]2NaOH(aq)+CaCl_{2}(aq)-->2NaCl(aq)+Ca(OH)_{2}(s)[/tex]:This reaction occurs as there is a formation of white precipitate of barium hydroxide.

So the correct answers are:

A)[tex]BaCl_{2}(aq)+Na_{2}SO_{4}(aq)-->BaSO_{4}(s)+2NaCl(aq)[/tex]

D)[tex]HCH_{3}COO(aq)+NaHCO_{3}(aq)-->NaCH_{3}COO(aq)+CO_{2}(g)+H_{2}O(l)[/tex]

E) [tex]2NaOH(aq)+CaCl_{2}(aq)-->2NaCl(aq)+Ca(OH)_{2}(s)[/tex]

Explanation:

A reaction between two different reactants can only occur if more reactive cation replaces less reactive cation.

Therefore, the given reactions are as follows.

  • [tex]BaCl_{2}(aq) + Na_{2}SO_{4}(aq) \rightarrow BaSO_{4}(s) + 2NaCl(aq)[/tex]

Here, reactive barium replaces less reactive sodium. Thus, there will be formation of barium sulphate and sodium chloride.

  • [tex]NaBr(aq) + KCl(aq) \rightarrow NaCl(aq) + KCl(aq)[/tex]

Here, sodium replaces potassium and result in the formation of NaCl and KBr. But the reaction shows products NaCl and KCl which are not possible. Thus, this reaction will not occur.

  • [tex]NH_{4}NO_{3}(aq) + AgClO_{3}(aq) \rightarrow AgNO_{3}(aq) + NH_{4}ClO_{3}(aq)[/tex]

Here, [tex]NH_{4}[/tex] replaces Ag and result in the formation of [tex]AgNO_{3}[/tex] and [tex]NH_{4}ClO_{3}[/tex]. Therefore, this reaction is possible.

  • [tex]CH_{3}COOH(aq) + NaHCO_{3}(aq) \rightarrow CH_{3}COONa(aq) + CO_{2}(g) + H_{2}O(l)[/tex]

Here, hydrogen of acetic acid is replaced by sodium atom along with formation of carbon dioxide and water. Thus, this reaction is also possible.

  • [tex]2NaOH(aq) + CaCl_{2}(aq) \rightarrow 2NaCl(aq) +Ca(OH)_{2}(s)[/tex]

Here, reactive Na atom replaces Ca atom and results in the formation of NaCl and calcium hydroxide. Thus, this reaction is also possible.

Therefore, identified equations that represent reactions that could occur are as follows.

  • [tex]BaCl_{2}(aq) + Na_{2}SO_{4}(aq) \rightarrow BaSO_{4}(s) + 2NaCl(aq)[/tex]
  • [tex]NH_{4}NO_{3}(aq) + AgClO_{3}(aq) \rightarrow AgNO_{3}(aq) + NH_{4}ClO_{3}(aq)[/tex]
  • [tex]CH_{3}COOH(aq) + NaHCO_{3}(aq) \rightarrow CH_{3}COONa(aq) + CO_{2}(g) + H_{2}O(l)[/tex]
  • [tex]2NaOH(aq) + CaCl_{2}(aq) \rightarrow 2NaCl(aq) +Ca(OH)_{2}(s)[/tex]

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