Consider the example data provided to complete the sentences. After colliding, G1 + G2 travels in a(n) direction as G1 travels before the collision, but at about the magnitude in velocity. The initial momentum of G2 (the magnitude or absolute value) is greater than G1 because its is greater than G1. The percent difference between the total momentum before and after the collision is %

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Answer:

Opposite

1/4

mass

0.0

Explanation:

I did the lab with the other answers that were posted but the "similar" part part was wrong. I tried "opposite" and I got it right.

The law of conservation of linear momentum states that the total momentum is a closed system is constant

The completed paragraph is presented as follows;

After colliding G1 + G2 travel in an opposite direction as G1 travels before collision, but at about 0.23 the magnitude in velocity. The initial momentum of G2 (the magnitude or absolute value) is greater than G1 because the mass is greater than G1. The percentage difference between the total momentum before and after the collision is 0%

The reasons the above values completing the passage are correct are as follows:

The given data is presented as follows:

[tex]\begin{array}{|l|cc|c|} \mathbf{Both \ Gliders \ Moving}&\mathbf{Before \ Collision}&&\mathbf{After \ Collision}\\&G1&G2 & G1 + G2\\m \, (kg)&0.5&0.8&1.3\\v \ (m/s)&3.00&-3.00&-0.69\\P \ (kg \cdot m/s)&1.50&-2.40&-0.90\end{array}\right][/tex]

From the data  in the above table, we have;

The velocity of G1 before collision = 3.00

The velocity of G1 + G2 after collision = -0.69 (negative sign means that the direction is reversed)

Therefore;

  • After colliding, G1 + G2, travel in an opposite direction to G1 before collision

The ratio of the magnitude of the velocity of G1 to G1 + G2 is 0.69/3 = 0.23

Therefore the magnitude of G1 + G2 is 0.23 times the magnitude of G1, and we have;

  • G1 + G2 moves at a magnitude of 0.23 the magnitude in velocity of G1

The initial momentum of G2 = 0.8 × -3.00 = -2.40

The initial momentum of G1 = 0.5 × 3.00 = 1.50

Therefore;

  • The initial momentum of G2 is greater than G1 because its mass is greater than G1

The total momentum before collision = 1.50 - 2.40 = -0.90

The total momentum after collision = -0.90

Therefore;

  • The percentage difference between the total momentum before and after the collision is 0%

Therefore, the correct options are; (1) Opposite, (2) 0.23 (3) Mass (4) 0%

The completed paragraph is presented at the top of the page

Learn more about conservation of linear momentum here:

https://brainly.com/question/11214803

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