find the coordinates of P ' if D o, 2.4 (x,y) is applied to the triangle below
Answer:
The coordinates of P' are (4.8,-4.8).
Step-by-step explanation:
The rule of dilation [tex]D_{o,2.4}(x,y)[/tex] represent the dilation with scale factor 2.4 and center at origin.
If the scale factor of the dilation is k and the center is (0,0), then
[tex](x,y)\rightarrow (kx,ky)[/tex]
Since the scale factor is 2.4, therefore
[tex](x,y)\rightarrow (2.4x,2.4y)[/tex]
From the given figure it is noticed that the coordinates of P are (2,-2). The coordinates of P' are
[tex]P(2,-2)\rightarrow P'(2.4(2),2.4(-2))[/tex]
[tex]P(2,-2)\rightarrow P'(4.8,-4.8)[/tex]
Therefore the coordinates of P' are (4.8,-4.8).