If rope is given in fourth harmonic
then it means that rope will have FOUR loops
One loop is always length of half wavelength
SO total length of the rope is given as
[tex]L = n\frac{\lambda}{2}[/tex]
now here we know
L = 6 m
n = Fourth Harmonic
[tex]6 = 4 * \frac{\lambda}{2}[/tex]
now we have
[tex]\lambda = 3 m[/tex]
so option A is correct
