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Ivan surveyed 49 randomly selected players from the 134 players of the soccer club teams to see if they wanted the games to be played on Saturdays or Sundays. Twenty-two of the players said that they preferred that the games be played on Saturdays. Ivan correctly determined that the margin of error, E, of his survey using a 99% confidence interval (z*score 2.58) is approximately 18% What is the 99% confidence level for players who prefer the games be played on Saturdays?

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mastersnowboarder24

Twenty-two of the players said that they preferred that the games be played on Saturdays. Ivan correctly determined that the margin of error, E, of his survey using a 99% confidence interval (z*score 2.58) is approximately 18%

Ivan surveyed 49 randomly select

InesWalston

Answer:

[tex]0.269,0.629[/tex]

Step-by-step explanation:

Ivan surveyed randomly selected 49 players out of 134.

22 of the players said that they preferred that the games be played on Saturdays.

Here,

p = proportion = [tex]\dfrac{22}{49}[/tex],

n = sample size = 49,

We know that,

[tex]\text{M.E}=Z_{critical}\cdot \sqrt{\dfrac{p(1-p)}{n}}[/tex]

It is given as 18% or 0.18

We also know that, confidence interval will be

[tex]=p\pm \text{M.E}[/tex]

Putting the values,

[tex]=\dfrac{22}{49}\pm 0.18[/tex]

[tex]=0.449\pm 0.18[/tex]

[tex]=0.269,0.629[/tex]


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