Look at the picture.
We have a parallelogram and two congruent triangles.
The formula of an area of a parallelogram:
[tex]A_P=bh[/tex]
We have b = 5 and h = 2. Substitute:
[tex]A_P=(5)(2)=10[/tex]
The formula of an area of a triangle:
[tex]A_T=\dfrac{bh}{2}[/tex]
We have b = 10 and h = 4. Substitute:
[tex]A_T=\dfrac{(10)(4)}{2}=\dfrac{40}{2}=20[/tex]
Area of this figure:
[tex]A=A_P+2A_T\\\\A=10+(2)(20)=10+40=50[/tex]
