25 points to whoever can answer this question !!
[tex]\dfrac{3}{4}+\left(-\dfrac{2}{3}\right)\\\\\text{the common denominator is (4)(3) = 12}\\\\\dfrac{3\cdot3}{4\cdot3}-\dfrac{2\cdot4}{3\cdot4}=\dfrac{9}{12}-\dfrac{8}{12}=\dfrac{9-8}{12}=\boxed{\dfrac{1}{12}}\to\boxed{c.}[/tex]