Answer:
[tex]x=\frac{3}{2}[/tex]
Step-by-step explanation:
By the quadratic formula,
The solutions of a quadratic equation ax² + bx + c = 0 is,
[tex]x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex]
Here, the given equation,
[tex]x^2-3x+\frac{9}{4}=0[/tex]
By comparing,
a = 1, b = -3, c = [tex]\frac{9}{4}[/tex]
Thus, solution of the given equation is,
[tex]x=\frac{3\pm \sqrt{9-4\times 1\times \frac{9}{4}}}{2}[/tex]
[tex]x=\frac{3\pm \sqrt{9-9}}{2}[/tex]
[tex]\implies x=\frac{3}{2}[/tex]
