Answer:
Force, [tex]F=7.3\times 10^3\ N[/tex]
Explanation:
Given that,
Mass of the car, m = 1000 kg
Initial speed of the car, u = 22 m/s
Finally, the brakes are applied, v = 0
Time, t = 3 s
We need to find the force required to stop the car. It is given by using second law of motion as :
[tex]F=m\times a[/tex]
[tex]F=\dfrac{m(v-u)}{t}[/tex]
[tex]F=\dfrac{1000(22)}{3}[/tex]
F = 7333.33 N
or
[tex]F=7.3\times 10^3\ N[/tex]
So, the force required to stop the car is [tex]7.3\times 10^3\ N[/tex]. Hence, this is the required solution.
