Answer:
(3,2)
Step by step explanation:
Please find the attachment.
Since we know that circumcenter of a right triangle lies exactly at the midpoint of hypotenuse.
Now we will draw a perpendicular bisector of line AB and by similar triangles bisector of AB will also bisect our hypotenuse into two equal parts.
Now we will draw a perpendicular bisector from 2 as 2 is the mid point of AB. Upon drawing a perpendicular bisector we can see that it bisect our hypotenuse at point (3,2).
Therefore,circumcenter of our right triangle will be on point (3,2).
