Which is the graph of the sequence defined by the function f(x + 1) = 2/3 f(x) if the initial value of the sequence is 108?
Answer:
The fourth graph.
Step-by-step explanation:
We have f(x + 1) so the x values will be increased by 1.
first value = 108 (when x = 1)
next value = 108 * 2/3 = 72 (when x = 2)
next = 72 * 2/ 3= 48 (when x = 3)
next = 48 * 2/3 = 32 (when x = 4)
Answer: Fourth graph is the correct graph.
Step-by-step explanation:
Since we have given that
Initial value of the sequence = f(x) = 108
And we have,
[tex]f(x+1)=\frac{2}{3}f(x)[/tex]
So, Put x = 1, we have
[tex]f(2)=\frac{2}{3}f(1)=\frac{2}{3}\times 108=72\\\\f(3)=\frac{2}{3}f(2)=\frac{2}{3}\times 72=48\\\\f(4)=\frac{2}{3}f(3)=\frac{2}{3}\times 48=32[/tex]
So, its coordinates must be
(1,108), (2,72), (3,48), (4,32)
and it is satisfied by the graph (4).
Hence, Fourth graph is the correct graph.