Answer:
Step-by-step explanation:
Alright, lets get started.
The given geometric series is :
∑[tex](-2)(-3)^{n-1}[/tex]
Plugging the value from n = 1 to n = 4
[tex](-2)(-3)^{1-1}+(-2)(-3)^{2-1}+(-2)(-3)^{3-1}+(-2)(-3)^{4-1}[/tex]
taking -2 common factor
[tex](-2)((-3)^{1-1}+(-3)^{2-1}+(-3)^{3-1}+(-3)^{4-1})[/tex]
[tex](-2)((-3)^{0}+(-3)^{1}+(-3)^{2}+(-3)^{3})[/tex]
[tex](-2)(1+(-3)+(9)+(-27))[/tex]
[tex]-2*-20[/tex]
[tex]40[/tex]
So the answer is 40 : Answer
Hope it will help :)
