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The answer is 9x^2-8x-6=0

The standard form of equation  11-4x=[tex](3x-2)^{2}[/tex]+1 is [tex]9x^{2} -8x-6=0[/tex].

What is equation?

An equation is  relationship between two or more variables expressed in equal to form. Equation of two variables look like ax+bx=c. It can be a polynomial , quadratic or cubic equation. When the highest power of x is 1 then it is known as linear equation, when the highest power of x is 2 then it is known as quadratic equation, when the highest power of x is 3 then it is known as cubic equation.

How to solve equation?

The equation which is given is 11-4x=[tex](3x-2)^{2} +1[/tex] can be solved as under:

11-4x=[tex](3x)^{2} +2^{2} -2*3x*2+1[/tex]  ([tex](A-B)^{2}=A^{2} +B^{2} -2AB[/tex])

11-4x=[tex]9x^{2} +4-12x+1[/tex]

Now take elements of same variables at one end of equal to sign.

[tex]9x^{2} +4-12x+1-11+4x=0[/tex]

[tex]9x^{2} -8x-6=0[/tex]

Hence the standard form of equation 11-4x=[tex](3x-2)^{2} +[/tex] is 9[tex]x^{2} -8x-6=0[/tex].

Learn more about equation at https://brainly.com/question/2972832

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