Respuesta :
Given:
volume of HBr = 430 ml = 0.430 L
Molarity of HBr = 0.230 M
Volume of HClO4 = 225 ml = 0.225 L
Molarity of HClO4 = 0.350 M
To determine:
Total moles of H+ when HBr and HClO4 are mixed
Explanation:
HBr and HClO4 are strong acids. Hence:
Concentration of H+ from HBr = 0.230 M
Concentration of H+ from HClO4 = 0.350 M
Now:
# moles of H+ from HBr = 0.430 L * 0.230 moles/L = 0.0989 moles
# moles of H+ from HClO4 = 0.225 L * 0.350 moles/L = 0.0788 moles
Total moles of H+ = 0.0989 + 0.0788 = 0.1777 moles
Ans: Total # moles of H+ is 0.178
The number of mole of Hydrogen ion H⁺ present in the final solution is 0.1777 mole
How to determine the mole of H⁺ in HBr
- Volume = 430 mL = 430 / 1000 = 0.43 L
- Molarity of HBr = 0.23 M
- Mole of HBr =?
Mole = Molarity x Volume
Mole of HBr = 0.23 × 0.43
Mole of HBr = 0.0989 mole
Dissociation equation
HBr(aq) —> H⁺(aq) + Br¯(aq)
From the balanced equation above,
1 mole of HBr contains 1 mole of H⁺.
Therefore,
0.0989 mole of HBr will also contain 0.0989 mole of H⁺
How to determine the mole of H⁺ in HClO₄
- Volume = 225 mL = 225 / 1000 = 0.225 L
- Molarity of HClO₄ = 0.35 M
- Mole of HClO₄ =?
Mole = Molarity x Volume
Mole of HClO₄ = 0.35 × 0.225
Mole of HClO₄ = 0.07875 mole
Dissociation equation
HClO₄(aq) —> H⁺(aq) + ClO₄¯(aq)
From the balanced equation above,
1 mole of HClO₄ contains 1 mole of H⁺.
Therefore,
0.07875 mole of HClO₄ will also contain 0.07875 mole of H⁺
How to determine the mole of H⁺ in the mixture
- Mole of H⁺ in HBr = 0.0989 mole
- Mole of H⁺ in HClO₄ = 0.07875 mole
- Total mole of H⁺ =?
Total mole of H⁺ = 0.0989 + 0.07875
Total mole of H⁺ = 0.1777 mole
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