what is the slope of the line described by the equation below? y=-x+8
We know that the Standard form of the line is : y = mx + c
Given Equation of the line is : y = -x + 8
Comparing with the Standard form, we can notice that : m = -1
So, the slope of the given line is -1
A is the Answer
The slope of line whose equation is y=-x+8 is equal -1.
The slope is basically upward or downward slant or inclination of degree. Slope is calculated by finding the ratio of the vertical change between two distinct points on a line. The formula of calculating slope from any two points is as under:
Slope=[tex](y_{2} -y_{1} )/(x_{2} -x_{1} )[/tex].
If a line is given in standard form of y=mx+c then we can find the slope by comparing because m is the slope in that equation.
The given equation of the line is y=-x+8. We can find the slope in two ways:one through just comparing and other one is through finding points and then calculate.
First way: Through comparing with standard form of equation.
Standard form of an equation is y=mx+c where m is slope.
The given equation is y=-x+8. When we compare both equations we will find that m=-1. So the slope is -1.
Second way: Through finding points first.
Given equation:y=-x+8
put x=0 , y will be 8.
put x=1 , y will be 7
points are (0,8),(1,7)
Formula of slope is [tex](y_{2} -y_{1} )/(x_{2} -x_{1} )[/tex]
Slope=(7-8)/(1=0)
=-1/1
=-1
Hence the slope of line whose equation is y=-x+8 is -1.
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