Respuesta :
Given:
Mass of MgBr2 = 0.500 g
To determine:
Number of anions in 0.500 g MgBr2
Explanation:
Molar mass of MgBr2 = 24 + 2 (80) = 184 g/mol
Moles of MgBr2 = 0.500 g/184 g.mol-1 = 0.00271 moles
Based on stoichiometry-
1 mole of MgBr2 has 1 mole of Mg2+ cations and 2 moles of Br- anions
Therefore, 0.00271 moles of MgBr2 will have: 2 * 0.00271 = 0.00542 moles of Br-
Now,
1 mole of Br- contains 6.023 * 10²³ anions
0.00542 moles of Br- contain: 0.00542 * 6.023*10²³ = 3.264*10²¹ anions
Ans: There are 3.264*10²¹ anions in 0.5 g of MgBr2
The study of chemicals is called chemistry. There are two types of solution in the chemistry and these are acid and base.
The correct answer to the question is as follows:-
What are moles?
- The mole is the base unit of the amount of substance in the International System of Units.
- It is defined as exactly 6.02214076×10²³ elementary entities, which may be atoms, molecules, ions, or electrons.
The data is given as follows:-
- Mass of MgBr2 = 0.500 g
- Number of anions in 0.500 g MgBr2
The calculation is as follows:-
- Molar mass of MgBr2 = [tex]24 + 2 (80) = 184[/tex]g/mol
- Moles of MgBr2 = [tex]0.500 g/184 g.mol-1 = 0.00271 moles[/tex]
According to the stoichiometry-
1 mole of MgBr2 has 1 mole of Mg2+ cations and 2 moles of Br- anions. Therefore, 0.00271 moles of MgBr2 will have: 2 * 0.00271 = 0.00542 moles of Br-
Now,
1 mole of Br- contains 6.023 * 10²³ anions and 0.00542 moles of Br- contain: 0.00542 * 6.023*10²³ = 3.264*10²¹ anions
Hence, the correct answer is [tex]3.264*10^{21}[/tex]
For more information about the question, refer to the link:-
https://brainly.com/question/15209553
