Answer: [tex]\frac{2x(5x + 1)}{4x - 1}[/tex]
Step-by-step explanation:
[tex]\frac{4x^{3}-12x^{2}}{4x^{2}+7x - 2}[/tex] ÷ [tex]\frac{2x^{2}-6x}{5x^{2}+11x + 2}[/tex]
= [tex]\frac{4x^{2}(x - 3)}{(4x - 1)(x + 2)}[/tex] ÷ [tex]\frac{2x(x - 3)}{(5x + 1)(x + 2)}[/tex]
= [tex]\frac{4x^{2}(x - 3)}{(4x - 1)(x + 2)}[/tex] x [tex]\frac{(5x + 1)(x + 2)}{2x(x - 3)}[/tex]
= [tex]\frac{2x(5x + 1)}{4x - 1}[/tex]
