Respuesta :
Answer: Compounds having the same empirical formula [tex]CH_2O[/tex] are:
[tex]C_2H_4O_2,C_3H_6O_3,C_5H_{10}O_5,C_6H_{12}O_6[/tex]
Explanation:
Empirical formula tells us about the proportion of the elements present in the compound but it do not tells us about the actual numbers of atoms of the elements present in the compound.
In given empirical formula [tex]CH_2O[/tex] that is proportion of C:H:O = 1:2:1
In [tex]C_2H_4O_2[/tex] the proportion of C:H:O =2:4:2= 1:2:1
In [tex]C_3H_6O_3[/tex] the proportion of C:H:O =3:6:3= 1:2:1
In [tex]CH_2O_2[/tex] the proportion of C:H:O =1:2:2= 1:2:2
In [tex]C_5H_{10}O_5[/tex] the proportion of C:H:O =5:10:5= 1:2:1
In [tex]C_6H_{12}O_6[/tex] the proportion of C:H:O =6:12:6= 1:2:1
Compounds having the given empirical formula [tex]CH_2O[/tex] are:
[tex]C_2H_4O_2,C_3H_6O_3,C_5H_{10}O_5,C_6H_{12}O_6[/tex]
The chemical compounds that have the empirical formula [tex]CH_2O[/tex] are:
A.C2H4O2
B.C3H6O3
D.C5H10O5
E.C6H12O6
An empirical formula can be defined as a formula that gives the smallest and simplest whole number ratio of the atoms of a chemical element found in a chemical compound.
The simplest whole number ratio of the atoms of [tex]CH_2O[/tex] is:
[tex]CH_2O[/tex] = 1:2:1
- 1 atom of carbon.
- 2 atoms of hydrogen molecule.
- 1 atom of oxygen.
For [tex]C_2H_4O_2[/tex]:
[tex]C_2H_4O_2[/tex] = 2:4:2 = 1:2:1
For [tex]C_3H_6O_3[/tex]:
[tex]C_3H_6O_3[/tex] = 3:6:3 = 1:2:1.
For [tex]CH_2O_2[/tex]:
[tex]CH_2O_2[/tex] = 1:2:2 = 1:1:1 (Incorrect)
For [tex]C_5H_{10}O_5[/tex]:
[tex]C_5H_{10}O_5[/tex] = 5:10:5 = 1:2:1
For [tex]C_6H_{12}O_6[/tex]:
[tex]C_6H_{12}O_6[/tex] = 6:12:6 = 1:2:1
Note:
- C is the chemical symbol of carbon.
- H is the chemical symbol of hydrogen.
- O is the chemical symbol of oxygen.
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