Answer:
The solution of the given equation is:
x=2 and x= -2
Step-by-step explanation:
We are given an quadratic equation as:
[tex]16x^2-64=0[/tex]
Now we are asked to find the solution of this equation i.e. we are asked to find the possible value of x that satisfy this equation.
[tex]16x^2-64=0\\\\\\16(x^2-4)=0\\\\\\x^2-4=0\\\\(x-2)(x+2)=0[/tex]
Since, we know that:
[tex]a^2-b^2=(a-b)(a+b)[/tex]
Hence, we have:
x=2 or x= -2
Hence, the solution of the equation are:
2 or -2.
