Respuesta :
As per the matrix theory the given system of equations can be written as:
[tex]AX=B[/tex]....................(Equation 1)
Where, A is the Coefficient Matrix (always a square matrix),
X is the variables' matrix (always a column matrix), and
B is the Constant Matrix (again always a column Matrix).
Since our's is a two system equation in two unknowns, we will have the coefficient matrix as a 2x2 square matrix and the other two matrices will be 2x1 column matrices.
Thus, the given system in terms of matrices will be:
[tex]\begin{bmatrix}3 &-4 \\ 1 & 6\end{bmatrix}\begin{bmatrix}x\\ y\end{bmatrix}=\begin{bmatrix}12\\ 10\end{bmatrix}[/tex]
Comparing the above equation with (Equation 1) we can clearly see that the correct coefficient matrix of the given system is:
[tex]A=\begin{bmatrix}3 &-4 \\ 1 & 6\end{bmatrix}[/tex]
