YaBoiSaltyPeanut YaBoiSaltyPeanut

04-11-2018
Mathematics

contestada

One Solution, infinitely many, or no solutions?

x-3y=27,2x=6y-14

Respuesta :

mrworldwide mrworldwide

04-11-2018

Ok, let’s take it step by step.
Take the first equation and solve for x.
x-3y=27
x=3y+27
Substitute x into the second equation.
2(3y+27)=6y-14
6y+68=6y-14
68=-14

Since 68 does not = -14, the system of equations has no solution.

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