Answer:
Option B is correct.
The common difference of the arithmetic sequence is, [tex]\frac{1}{8}[/tex]
Step-by-step explanation:
Common difference(d) states that take any pair of successive numbers, and subtract the first from the second.
Given the arithmetic sequence:
1/4 , 3/8, 1/2...
⇒[tex](a_1)[/tex] = 1/4, [tex]a_2 = \frac{3}{8}[/tex] , [tex]a_3 = \frac{1}{2}[/tex] and so on..
By definition of common difference
[tex]a_2 -a_1 = \frac{3}{8}-\frac{1}{4} = \frac{3-2}{8} = \frac{1}{8}[/tex]
[tex]a_3 -a_2= \frac{1}{2}-\frac{3}{8} = \frac{4-3}{8} = \frac{1}{8}[/tex] and so on..
⇒[tex]d = a_2-a_1 = a_3-a_2=.....= \frac{1}{8}[/tex]
Therefore, the common difference of the arithmetic sequence is, [tex]\frac{1}{8}[/tex]
