Answer:
[tex] x = \dfrac{7}{12} [/tex]
Step-by-step explanation:
[tex] 64 \cdot 16^{-3x} = 16^{3x-2} [/tex]
[tex] 4^3 \cdot (4^2)^{-3x} = (4^2)^{3x-2} [/tex]
[tex] 4^3 \cdot 4^{-6x} = 4^{6x-4} [/tex]
[tex] 4^{-6x+3} = 4^{6x-4} [/tex]
[tex] -6x+3 = 6x-4 [/tex]
[tex] -12x = -7 [/tex]
[tex] x = \dfrac{7}{12} [/tex]
