First: we must find the equation of the line passes through the points (-3, 0) and (0,6).
The slope-intercept form:
[tex]y=mx+b\\\\m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]
m - slope
b - y-intercept → (0, b)
Therefore we have b = 6.
Calculate the slope:
[tex]m=\dfrac{6-0}{0-(-3)}=\dfrac{6}{3}=2[/tex]
We have the equation of the line l: y = 2x + 6.
The equation of the graph in attachment is |y|.
Answer: y = |2x + 6|
