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Suppose that rectangle ABCD is dilated to A'B'C'D' using vertex B as the center and a magnitude of 2. What are the coordinates of D'?


A) (3, 4)
B) (8, 4)
C) (4, -8)
D) (4, -11)

Suppose that rectangle ABCD is dilated to ABCD using vertex B as the center and a magnitude of 2 What are the coordinates of D A 3 4 B 8 4 C 4 8 D 4 11 class=

Respuesta :

D

the coordinates of B(4, 3 ) and D(4, - 4 )

BD = d - b ← position vector representation

     = <4, - 4> - <4, 3> = <0, - 7>

BD' = 2BD = 2<0, - 7> = <0, - 14>

D' = (4 + 0, 3 - 14 ) = (4, - 11 ) → D


Answer:

The correct option is D. (4, -11)

Step-by-step explanation:

By looking at the diagram given :

The coordinates of B are : (4, 3 ) and D are : (4, - 4 )

Now, Using position vector representation

BD can be written as :

BD = D - B

     = <4, - 4> - <4, 3>

     = <0, - 7>

Now, rectangle ABCD is dilated to A'B'C'D' using vertex B as the center and a magnitude of 2.

⇒ BD' = 2 × BD

          = 2 × <0, - 7>

          = <0, - 14>

So, Coordinates of D' = (4 + 0, 3 - 14 )

                                     = (4, - 11 )

Therefore, The correct option is D. (4, -11)

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