If f(x)=2x^2-3x what is the value of f(5)

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qabtt qabtt · Answer 1 · 2018-10-06T00:31:18+02:00

To find [tex]f(5)[/tex], all you need to do is substitute 5 in for [tex]x[/tex] in [tex]f(x)[/tex]. This allows us to find our answer:

[tex]f(5) = 2(5)^2 - 3(5)[/tex]

[tex]f(5) = 50 - 15[/tex]

[tex]f(5) = 35[/tex]

The answer is f(5) = 35.

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HelpfulHelp HelpfulHelp · Answer 2 · 2018-10-06T00:35:41+02:00

The answer is 35

Here's how I got my answer:

Step 1: Replace all x's with [tex]5[/tex]. Leaving us with [tex]2(5)^2-3(5)[/tex]

Step 2: Solve [tex]5^2[/tex], which is [tex]25[/tex]. That leaves us with [tex]2(25)-3(5)[/tex]

Step 3: Solve [tex]2(25)[/tex], which is [tex]50[/tex]. That leaves us with [tex]50-3(5)[/tex]

Step 4: Solve [tex]3(5)[/tex], which is [tex]15[/tex]. That leaves us with [tex]50-15[/tex]

Step 5: Simplify 50-15 to get your answer, 35.