[tex]\text{The formula of a perimeter of a rectangle:}\\\\P=2(w+l)\\\\\text{we have}\\w:l=3:2\to w=\dfrac{3}{2}l,\ P=55\ cm\\\\\text{substitute}\\\\55=2\left(\dfrac{3}{2}l+l\right)\\\\55=2\cdot\left(\dfrac{3}{2}l+\dfrac{2}{2}l\right)\\\\55=2\cdot\dfrac{5}{2}l\\\\55=5l\ \ \ \ \ |:5\\\\l=11\ cm\\\\w=\dfrac{3}{2}\cdot11=\dfrac{33}{2}=16.5\ cm\\\\Answer:\ b.\ 11\ cm,\ 11\ cm,\ 16.5\ cm,\ 16.5\ cm[/tex]
