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A man spent 15 minutes every day feeding the pigs. He spent 3 minutes less in the evening than he did after breakfast. For how many minutes did the man fed the pigs each time?

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Let's call the time he spent feeding the pigs after breakfast [tex]b[/tex] and the time he spent feeding the pigs in the evening [tex]e[/tex]. Using the information in the problem, we can say that [tex]e = b - 3[/tex], since he spent 3 minutes less than the amount of time at breakfast, which is [tex]b[/tex].


We can also say that [tex]e + b = 15[/tex], since he spent 15 minutes each day in total feeding the pigs. If we substitute in what we found for [tex]e[/tex], then we can find the equation [tex](b - 3) + b = 15[/tex], which we can simplify, as shown below:

[tex](b - 3) + b = 15[/tex]

[tex]2b - 3 = 15[/tex]

[tex]2b = 18[/tex]

[tex]b = 9[/tex]


We have found that he spent 9 minutes after breakfast feeding the pigs. We can find [tex]e[/tex] by substituting in what we found for [tex]b[/tex] into our earlier equation:

[tex]e = b - 3[/tex]

[tex]e = 9 - 3[/tex]

[tex]e = 6[/tex]


He spent 9 minutes feeding the pigs after breakfast and 6 minutes feeding the pigs in the evening.

the answer is  189mins

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