[tex]4y-8-2y+5=0\\\\(4y-2y)+(-8+5)+0\\\\2y-3=0\qquad|\text{add 3 to both sides}\\\\2y=3\qquad|\text{divide both sides by 2}\\\\y=\dfrac{3}{2}\\\\\boxed{y=1\dfrac{1}{2}}\to\boxed{c.}[/tex]
4y - 8 - 2y + 5 = 0
2y - 3 = 0
2y = 3
y = 3/2
