Mass x SH x °C (or K) ΔT
= 75g x 0.45J/g/K x 6.0 ΔT
= 202.5 Joules of heat absorbed.
(202.5J / 4.184J/cal = 48.4 calories).
I guess that is the answer
Hello friend ☺
ΔH = MCΔT
ΔH = to the amount of energy or change in energy (J)
M = mass of substance
C = waters specific heat capacity
ΔT = change in temperature
and so ΔH = 75.20 * 4.18 * ( 28-22 ) = 1886.016 J
Thanks ❤
