[tex]Solution, 3x-\frac{1}{2}y+\frac{22}{3}y-\frac{5}{6}x=\frac{13x+41y}{6}[/tex]
[tex]Steps:[/tex]
[tex]\mathrm{Group\:like\:terms}, =3x-\frac{5}{6}x-\frac{1}{2}y+\frac{22}{3}y[/tex]
[tex]\mathrm{Add\:similar\:elements:}\:3x-\frac{5}{6}x=\frac{13}{6}x, =\frac{13}{6}x-\frac{1}{2}y+\frac{22}{3}y[/tex]
[tex]\mathrm{Add\:similar\:elements:}\:-\frac{1}{2}y+\frac{22}{3}y=\frac{41}{6}y, =\frac{13}{6}x+\frac{41}{6}y[/tex]
[tex]\mathrm{Multiply\:}\frac{13}{6}x\::\quad \frac{13x}{6}, =\frac{13x}{6}+\frac{41}{6}y[/tex]
[tex]\mathrm{Multiply\:}\frac{41}{6}y\::\quad \frac{41y}{6}, =\frac{13x}{6}+\frac{41y}{6}[/tex]
[tex]\mathrm{Apply\:rule}\:\frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}, =\frac{13x+41y}{6}[/tex]
The correct answer is [tex]=\frac{13x+41y}{6}[/tex]
Hope this helps!!!
