Horizontal distance covered is given as
[tex]x = 22 m[/tex]
vertical distance climbed by is given as
[tex]y = 4.8 m[/tex]
now we need top find the angle made by the displacement vector with respect to horizontal
So here we will say that we can use trigonometry to find out the angle with horizontal
The formula is given as
[tex]tan\theta = \frac{opposite \: side}{adjacent \: side}[/tex]
here given that
opposite side = 4.8 m
adjacent side = 22 m
now we can plug in all data in above equation
[tex]tan\theta = \frac{4.8}{22}[/tex]
[tex]tan\theta = 0.22[/tex]
[tex]\theta = tan^{-1}0.22[/tex]
[tex]\theta = 12.3 degree[/tex]
so here the displacement will make 12.3 degree angle with horizontal
