[tex]\dfrac{2}{3}(4x-5)=8\qquad|\text{use the division property of equality}\\\\\dfrac{2}{3}(4x-5):\dfrac{2}{3}=8:\dfrac{2}{3}\\\\\dfrac{2}{3}(4x-5)\cdot\dfrac{3}{2}=8\cdot\dfrac{3}{2}\\\\4x-5=4\cdot3\\\\4x-5=12\qquad|\text{use addition property of equality}\\\\4x-5+5=12+5\\\\4x=17\qquad|\text{use the division property of equality}\\\\4x : 4=17:4\\\\x=\dfrac{17}{4}[/tex]
